Given: \overline{BD} \cong \overline{AC}

BD ≅ AC

and \overline{BA} \cong \overline{DC}.

BA ≅ DC

Prove: \triangle BAD \cong \triangle CDA△BAD≅△CDA.

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# Given: \overline{BD} \cong \overline{AC}
BD ≅ AC
and \overline{BA} \cong \overline{DC}.
BA ≅ DC
Prove: \triangle BAD \cong \triangle CDA△BAD≅△CDA.

Given: \overline{BD} \cong \overline{AC}

BD ≅ AC

and \overline{BA} \cong \overline{DC}.

BA ≅ DC

Prove: \triangle BAD \cong \triangle CDA△BAD≅△CDA.