Given: \overline{BD} \cong \overline{AC} BD ≅ AC and \overline{BA} \cong \overline{DC}. BA ≅ DC Prove: \triangle BAD \cong \triangle CDA△BAD≅△CDA.

Given: \overline{BD} \cong \overline{AC}

BD ≅ AC
and \overline{BA} \cong \overline{DC}.
BA ≅ DC
Prove: \triangle BAD \cong \triangle CDA△BAD≅△CDA.


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